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Delhi University MCA Train PYQ


Delhi University MCA PYQ 2020
Two trains each 500 metres long, are running in opposite directions on parallel tracks. If their speeds are 50 km/hr and 40 km/hr respectively, the time taken by the slower train to pass the driver of the faster one is _______seconds





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Solution

Relative speed = (50 + 40) km/hr
=(90×518)m/sec
=25 m/sec.
We have to find the time taken by the slower train to pass the Driver of the faster train and not the complete train.
So, distance covered = Length of the slower train.
Therefore, Distance covered = 500 m.
∴ Required time (500×125​)=20sec.


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